The reason why they picked 3.05 and not 3 is to stymie people trying to go for the easy solution involving an inscribed hexagon.
The textbook answer is to use an inscribed dodecagon (12-gon).
The elegant answer (using pure geometry) is to use an inscribed decagon (10-gon), since it's the smallest n-gon you'll need and also has beautiful golden ratios.
The most 'elegant' answer is to use the 1968 Putnam integral. Though this might be a bit overkill and relies on more recent mathematical developments (i.e. calculus, not just geometry). But it is very, very beautiful and succinct.
They are also lot of other possible proofs, some more elegant than the others, and some downright cheeky. Though knowing the Baka Group they'll probably go for something like 𝜋 = 3.142... > 3.05, which doesn't count as a proof because it's tautological. And by "they" I mean Dai-chan. The rest will probably just go "wuhhh" or "Is pie tasty?"
The reason why they picked 3.05 and not 3 is to stymie people trying to go for the easy solution involving an inscribed hexagon.
The textbook answer is to use an inscribed dodecahedron (12-gon).
The elegant answer (using pure geometry) is to use an inscribed decahedron (10-gon), since it's the smallest n-gon you'll need and also has beautiful golden ratios.
The most 'elegant' answer is to use the 1968 Putnam integral. Though this might be a bit overkill and relies on more recent mathematical developments (i.e. calculus, not just geometry). But it is very, very beautiful and succinct.
They are also lot of other possible proofs, some more elegant than the others, and some downright cheeky. Though knowing the Baka Group they'll probably go for something like 𝜋 = 3.142... > 3.05, which doesn't count as a proof because it's tautological. And by "they" I mean Dai-chan. The rest will probably just go "wuhhh" or "Is pie tasty?"
So basically what you're saying is I can't get in to Tokyo University.
School had accepted our (technical education) class answer of grabbing a measuring tape and measuring both the circumference and the diameter of the teacher's cup.
Apparently not the first time our side of the education system used that bypass.
The reason why they picked 3.05 and not 3 is to stymie people trying to go for the easy solution involving an inscribed hexagon.
The textbook answer is to use an inscribed dodecagon (12-gon).
The elegant answer (using pure geometry) is to use an inscribed decagon (10-gon), since it's the smallest n-gon you'll need and also has beautiful golden ratios.
The most 'elegant' answer is to use the 1968 Putnam integral. Though this might be a bit overkill and relies on more recent mathematical developments (i.e. calculus, not just geometry). But it is very, very beautiful and succinct.
They are also lot of other possible proofs, some more elegant than the others, and some downright cheeky. Though knowing the Baka Group they'll probably go for something like 𝜋 = 3.142... > 3.05, which doesn't count as a proof because it's tautological. And by "they" I mean Dai-chan. The rest will probably just go "wuhhh" or "Is pie tasty?"
I’m no math whiz, but I’m curious what would make a mathematical proof “cheeky”
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